B, (layer C is the youngest layer) :)
Answer:
C) 64% AA, 32% Aa, 4% aa
Explanation:
The frequency of dominant allele A is = 80% = 0.8
Since the population is in Hardy-Weinberg equilibrium, p+ q = 1
Here, p= frequency of dominant allele
q = frequency of recessive allele
Given, p= 0.8
So, q = 1-p = 1-0.8= 0.2
Frequency of genotype AA = p2 = 0.8 x 0.8 = 0.64 = 64%
Frequency of genotype aa = q2 = 0.2 x 0.2 = 0.04 = 4%
Frequency of genotype Aa = 2pq = 2 x 0.8 x 0.2 = 0.32 = 32%
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