(x-p)(x-q)
x^2 -qx -px + pq
x^2 -(q+p) x +pq
so the constant here is the product of p & q
the answer is A
For this case, we have to:
By definition, we know:
The domain of
is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.
So, we have:
with
:
is defined.
with
is also defined.
has a domain from 0 to ∞.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when
.
While
if it is defined for
.
Answer:

Option b
8x+6-5x=1
3x+6=1
please vote my answer branliest. Thanks.
Answer:
y=3
Step-by-step explanation:
(i used point-slope form which is (y1-y2)=m(x1-x2))
(10-y)=7(4-3)
10-y=7
-y=-3
y=3
The slope of the line (m) = 3/1 = 3
and the y intercept is at (0,3) that is y = 3 so b = 3
using the slope intercept form y = mx + b
m = 3 and b = 3
so answer is y = 3x + 3