A car drove 330 miles in 6 hours at a constant rate. If the car’s rate of travel slows by 10 mph, what is the new, slower rate o
1 answer:
Answer:
45 mph
Step-by-step explanation:
Given: Distance travelled= 330 miles
Time taken= 6 h
Lets find out speed of car drove.
Formula;
Speed=
∴ Car´s speed is 55 mph.
As we have been informed that car´s rate of travel slows by 10 mph
∴ we have to reduce the current speed of car by 10 mph;
The new slower rate of travel is 45 mph.
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Answer:
Therefore the solution set is (x , y) = ( 2 , 1 )
Step-by-step explanation:
Given:
...............Equation ( 1 )
...............Equation ( 2 )
...............Equation ( 3 )
To Find:
x = ?
y = ?
Solution:
Using Substitution Method we will have
Substitute above ' y ' Equation 3 in Equation 1 we get
Now Substitute ' x ' in Equation 3 we get
Therefore the solution set is (x , y) = ( 2 , 1 )
This is what I have but it doesn't match with your answers
Mug 2 can hold the most as its volume is greater than that of mug 1
Step-by-step explanation:
To find out which mug holds more let us find the volume of each mug
As we know
Height of first mug =H1= 3 in
Diameter of first mug= D1= 5.5 in
Radius of first mug = R1=
= 2.75 in
The volume of first mug M1 is V1
The formula used will be
V=πr2h
V1 will be equal to
V1 = 51.81
Similarly
As we know
Height of second mug = H2= 4 in
Diameter of second mug = D2 = 4.5 in
Radius of second mug = R2=
= 2.25 in
The volume of second mug M2 is V2
the formula used will be
V=πr2h
V2 will be equal to
V2 = 56.52
So as V2(56.52) is greater than V1(51.81) so mug 2 can hold the most
Keywords: volume of cylinder
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