Question

A car drove 330 miles in 6 hours at a constant rate. If the car’s rate of travel slows by 10 mph, what is the new, slower rate of travel?

Answer 1

Answer:

45 mph

Step-by-step explanation:

Given: Distance travelled= 330 miles

           Time taken= 6 h

Lets find out speed of car drove.

Formula; $Speed= \frac{Distance}{time}$

Speed= $\frac{330}{6} = 55\ mph$

∴ Car´s speed is 55 mph.

As we have been informed that car´s rate of travel slows by 10 mph

∴ we have to reduce the current speed of car by 10 mph; $(55-10)= 45\ mph$

The new slower rate of travel is 45 mph.