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Elza [17]
3 years ago
6

A car drove 330 miles in 6 hours at a constant rate. If the car’s rate of travel slows by 10 mph, what is the new, slower rate o

f travel?
Mathematics
1 answer:
12345 [234]3 years ago
5 0

Answer:

45 mph

Step-by-step explanation:

Given: Distance travelled= 330 miles

           Time taken= 6 h

Lets find out speed of car drove.

Formula; Speed= \frac{Distance}{time}

Speed= \frac{330}{6} = 55\ mph

∴ Car´s speed is 55 mph.

As we have been informed that car´s rate of travel slows by 10 mph

∴ we have to reduce the current speed of car by 10 mph; (55-10)= 45\ mph

The new slower rate of travel is 45 mph.

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_________________________

given

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