A car drove 330 miles in 6 hours at a constant rate. If the car’s rate of travel slows by 10 mph, what is the new, slower rate o
1 answer:
Answer:
45 mph
Step-by-step explanation:
Given: Distance travelled= 330 miles
Time taken= 6 h
Lets find out speed of car drove.
Formula;
Speed=
∴ Car´s speed is 55 mph.
As we have been informed that car´s rate of travel slows by 10 mph
∴ we have to reduce the current speed of car by 10 mph;
The new slower rate of travel is 45 mph.
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Answer:
y = 3x - 9
Step-by-step explanation:
We first need to find the slope (m)
m = =
=
= 3
y = mx + b
y = 3x + b
(4, 3)
y = 3x + b
3 = 3(4) + b
3 = 12 + b
-12 -12
-9 = b
(1, –6)
y = 3x + b
-6 = 3(1) + b
-6 = 3 + b
-3 -3
-9 = b
y = 3x - 9
To check: (1, –6)
y = 3x - 9
-6 = 3(1) - 9
-6 = 3 - 9
-6 = -6
Hope this helps!