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kirill [66]
4 years ago
13

Convert to pints 7 quarts

Mathematics
2 answers:
Margaret [11]4 years ago
8 0
14 pints. You multiply by 2. :-)
adell [148]4 years ago
3 0
1 quart = 2 pints 

Convert:-

7 × 2 = 14

7 quarts = 14 pints 
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Please answer this correctly
Nana76 [90]

20% of the students chose a cupcake = 20 / 100: Shade 20 squares.

20 / 100 = x / 55

100x = 1100

x = 11 students who chose a cupcake

Hope this helps!! :)

8 0
3 years ago
A random sample of n measurements was selected from a population with unknown mean mu and standard deviation sigmaequals50 for e
Andre45 [30]

Answer:

a) (26.50;57.50)

b) (117.34;128.66)

c) (12.13;27.87)

d) (-4.73;11.01)

e) No. Since the sample sizes are large (n ≥ 30), the central limit theorem  guarantees that \bar x is approximately normal, so the confidence intervals are valid

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval is given by this formula:

\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}   (1)

And for a 95% of confidence the significance is given by \alpha=1-0.95=0.05, and \frac{\alpha}{2}=0.025. Since we know the population standard deviation we can calculate the critical value z_{0.025}= \pm 1.96

Part a

n=40,\bar X=42,\sigma=50

If we use the formula (1) and we replace the values we got:

42 - 1.96 \frac{50}{\sqrt{40}}=26.50  

42 + 1.96 \frac{50}{\sqrt{40}}=57.50  

The 95% confidence interval is given by (26.50;57.50)

Part b

n=300,\bar X=123,\sigma=50

If we use the formula (1) and we replace the values we got:

123 - 1.96 \frac{50}{\sqrt{300}}=117.34  

123 + 1.96 \frac{50}{\sqrt{300}}=128.66  

The 95% confidence interval is given by (117.34;128.66)

Part c

n=155,\bar X=20,\sigma=50

If we use the formula (1) and we replace the values we got:

20 - 1.96 \frac{50}{\sqrt{155}}=12.13  

20 + 1.96 \frac{50}{\sqrt{155}}=27.87  

The 95% confidence interval is given by (12.13;27.87)

Part d

n=155,\bar X=3.14,\sigma=50

If we use the formula (1) and we replace the values we got:

3.14 - 1.96 \frac{50}{\sqrt{155}}=-4.73  

3.14 + 1.96 \frac{50}{\sqrt{155}}=11.01  

The 95% confidence interval is given by (-4.73;11.01)

Part e

No. Since the sample sizes are large (n ≥ 30), the central limit theorem  guarantees that \bar x is approximately normal, so the confidence intervals are valid

8 0
3 years ago
Which conditional statement has a false converse?
exis [7]

Consider the converses:

a) If two planes have no points in common, then they are parallel. (true)

b) If a point lies on the y-axis, then it has x-coordinate 0. (true)

c) If two angles have the same measure, then they are congruent. (true)

d) If a figure has four sides, then it is a square. (FALSE) (A figure with 4 sides may not even be a plane figure.)

8 0
4 years ago
Graph y-4= -2/5 (x-1)
aleksklad [387]

Answer:

Step-by-step explanation:

3 0
4 years ago
DOLCS. 110W mally exld uunuis un
horsena [70]

Answer:

40 more pieces

Step-by-step explanation:

Cody wants to EQUALLY divide 680 candy amongst 45 friends.

That can't be possible because 45 doesn't evenly go into 680. If we do the division, we see:

680/45 = 15.11

So there are some remaining. How many?

45 * 15 = 675

So, the rest are remaining (680 - 675 = 5)

For Cody to equally distribute, he needs how many more? That number should be multiple of 45.

Since 45 * 15 = 675 which is less than 680, to get next number that 45 goes into, we do 45 * 16 = 720

Cody already has 680, he needs 720 altogether for EQUAL SHARE. He would need:

720 - 680 = 40 candy more

7 0
3 years ago
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