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3 years ago

A line has a slope of 2 and contains the points (1, 3) and (2, y). The value of y is

1 answer:

8 0

Y=mx+b

y=2x+b

point (1,3)

substitute to find b

3=2*1+b

3=2+b

b=1

equation is y=2x+1

point (2,y)

substitute to get y

y=2*2+1

y=4+1

y=5

point (2,5)

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Find the equation lines (4, 5)(7, 3)

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Step-by-step explanation:

Hey there!

The equation of a st.line passing through points (4,5) and (7,3) is;

$(y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)$

Put all values.

$(y - 5) = \frac{3 - 5}{7 - 4} (x - 4)$

Simplify it.

$(y - 5) = \frac{ - 2}{3} (x - 4)$

$3(y - 5) = - 2x + 8$

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$2x + 3y - 23 = 0$

Therefore therequired equation is 2x+3y-23=0.

Hope it helps..

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