I believe its the third answer
Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
materials with a density less than water will float
Answer:
Explanation:
from t = .3 to t = .33 , velocity appears to be uniform .
uniform velocity = .22 m /s
displacement will be area of the v-t graph which is a rectangle .
= .22 x ( .33 - .3 )
= .22 x .03
= 66 x 10⁻⁴ m
= 6.6 mm .
