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kakasveta [241]
4 years ago
13

Two charged point particle are located at two vertices of an equilateral triangle and the electric field is zero at the third ve

rtex. We conclude: A) the two particles have charges with opposite signs and the same magnitude B) the two particles have charges with opposite signs and different magnitudes C) the two particles have identical charges D) the two particles have charges with the same sign but different magnitudes E) at least one other charged particle is present
Physics
1 answer:
Debora [2.8K]4 years ago
4 0

Answer:

Option E

Explanation:

In the presence of two point charges at the two vertices of an equilateral triangle, the resultant electric field at the third vertex due to these charges can not be zero whether the charges are identical or not.

The reason being that only of the x or y component of the field can be cancelled out in either case still the total field can't be reduced to zero.

This can only be achieved if another charge is present.

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\ describes the size and distance relationship of our sun and the nearest star?
Zolol [24]

Answer: Two marbles separated by 300 kilometers

Explanation: Hope i helped have a great day and please mark brainliest i would appreciate it!

7 0
3 years ago
Using a mass of 1. 8 g and the volume displaced by the sample, calculate the sample's density. Question 17 options: 0. 17 g/mL 0
LUCKY_DIMON [66]

The sample's density with respect to the volume it displaces is equal to: C. 0. 60 g/mL

<u>Given the following data:</u>

  • Mass = 1.8 grams
  • Initial volume = 20 mL
  • Final volume = 23 mL

To calculate the sample's density:

First of all, we would determine the volume displaced by the sample;

Volume \;displaced = 23-20

Volume displaced = 3 mL

Density can be defined as mass all over the volume of an object. Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

Density = \frac{Mass}{Volume}

Substituting the given parameters into the formula, we have;

Density = \frac{1.8}{3}

Density = 0.60 g/mL

Read more: brainly.com/question/18320053

8 0
3 years ago
A 0.37-kg object connected to a light spring with a force constant of 23.2 N/m oscillates on a frictionless horizontal surface.
mars1129 [50]

Answer:

a) v = 31.67 cm / s , b)   v = -29.36 cm / s , c) v= 29.36 cm/s, d) x = 3.46 cm

Explanation:

The angular velocity in a simple harmonic movement is

       w = √ K / m

       w = √ 23.2 / 0.37

       w = 7,918 rad / s

a) the expression against the movement is

        x = A cos (wt + Ф)

Speed ​​is

        v = dx / dt = - A w sin (wt + Ф)

 The maximum speed occurs for cos = ± 1

        v = A w

        v = 4.0 7,918

        v = 31.67 cm / s

b) as the object is released from rest

        0 = -A w sin (0+ Фi)

        sin Ф = 0

         Ф = 0

The equation is

        x = 4.0 cos (7,918 t)

        v = -4.0 7,918 sin (7,918 t)

        v = - 31.67 sin (7.918t)

     

Let's look for the time for a displacement of x = 1.5 cm, remember that the angles must be in radians

          7,918 t = cos⁻¹ 1.5 / 4.0

          t = 1,186 / 7,918

          t = 0.1498 s

We look for speed

         v = -31.67 sin (7,918 0.1498)

         v = -29.36 cm / s

c) if the object passes the equilibrium equilibrium position again at this point the velocity has the same module, but the opposite sign

         v = 29.36 cm / s

d) let's look for the time for the condition v = v_max / 2

         31.67 / 2 = 31.67 sin ( 7,918 t)

          7.918t = sin⁻¹ 0.5

         t = 0.5236 / 7.918

         t = 0.06613

With this time let's look for displacement

         x = 4.0 cos (7,918 0.06613)

        x = 3.46 cm

6 0
3 years ago
The starter motor of a car engine draws a current of 140 A from the battery. The copper wire to the motor is 4.20 mm in diameter
GenaCL600 [577]

Answer:

(a)106.4C

b)0.5676mm

Explanation:

(a)To get the charge that have passed through the starter then The current will be multiplied by the duration

I= current

t= time taken

Q= required charge

Q= I*t = 140*0.760 = 106.C

(b) b. How far does an electron travel along the wire while the starter motor is on?(mm)

diameter of the conductor is 4.20 mm

But Radius= diameter/2= 4.20/2=

The radius of the conductor is 2.1mm, then if we convert to metre for consistency same then

radius of the conductor is 0.0021m.

We can now calculate the area of the conductor which is

A = π*r^2

= π*(0.0021)^2 = 13.85*10^-6 m^2

We can proceed to calculate the current density below

J = 140/13.85*10^-6 = 10108303A/m

According to the listed reference:

Where e= 1.6*10^-19

n= 8.46*10^28

Vd = J/(n*e) = 10108303/ ( 8.46*10^28 * 1.6*10^-19 ) =0.0007468m/s=0 .7468 mm/s

Therefore , the distance traveled is:

x = v*t = 0.7468 * 0.760 = 0.5676mm

7 0
3 years ago
Jake drops a book out of a window from a height of 10 meters. At what velocity does the book hit the ground?.
Lelechka [254]
I think the best way to answer to this kind of question because some of the elements are missing specially the mass of the book is just states the variables and assigned as the mass of an object. So the initial velocity of an object starts at zero and increase rapidly by 9.8 m/s^2 because it is due to gravity
4 0
3 years ago
Read 2 more answers
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