1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kakasveta [241]
3 years ago
13

Two charged point particle are located at two vertices of an equilateral triangle and the electric field is zero at the third ve

rtex. We conclude: A) the two particles have charges with opposite signs and the same magnitude B) the two particles have charges with opposite signs and different magnitudes C) the two particles have identical charges D) the two particles have charges with the same sign but different magnitudes E) at least one other charged particle is present
Physics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

Option E

Explanation:

In the presence of two point charges at the two vertices of an equilateral triangle, the resultant electric field at the third vertex due to these charges can not be zero whether the charges are identical or not.

The reason being that only of the x or y component of the field can be cancelled out in either case still the total field can't be reduced to zero.

This can only be achieved if another charge is present.

You might be interested in
2 Points
mezya [45]
The advantage is that we do not run out of resources and a disadvantage is that is dangerous when a “human” gets too close and gets sick by the radiation.
5 0
3 years ago
An electron is pushed into an electric field where it acquires a 1-v electrical potential. suppose instead that two electrons ar
Lapatulllka [165]
1V electrical potential 
4 0
3 years ago
Read 2 more answers
A small glass bead has been charged to +20 nC. A small metal ball bearing 1.0 cm above the bead feels a 0.018 N downward electri
Alla [95]

Answer:

q=1\times10^{-8}C

Explanation:

Let the charge on the ball bearing is q.

charge on glass bead, Q = 20 nC = 20 x 10^-9 C

Force between them, F = 0.018 N

Distance between them, d = 1 cm = 0.01 m

By use of Coulomb's law in electrostatics

F=\frac{KQq}{d^{2}}

By substituting the values

0.018=\frac{9\times10^{9}\times20\times10^{-9}q}{0.01^{2}}

q=1\times10^{-8}C

Thus, the charge on the ball bearing is q=1\times10^{-8}C

7 0
3 years ago
You’ve made the hypothesis that the stepper the slope , the faster a ball will be rolling when it reaches the bottom .
BigorU [14]

Answer:

B) how steep the slope is

Explanation:

Because you have to know how is the influence of the steep of the slope in the time that a ball reaches the bottom. The steep of the slope is the variable that you would have to change in an experiment.

I hope this is useful for you

regards

4 0
3 years ago
IMPORTANTT!!! SOLVEE!!! and EXPLAIN!!!
Pepsi [2]
My answer -

I believe that the answer is (A).

P.S

Happy to help you have an AWESOME!! day
5 0
3 years ago
Other questions:
  • A solid object has a mass of 104 kg and a volume of 1,278 m3. What is its density? 0.081 kg/m3 12.29 g/cm3 132912.00 g/cm3 canno
    11·2 answers
  • Which circle passes through more continents antarctic or arctic
    6·1 answer
  • Climate is best described as the
    10·1 answer
  • The electric field strength E is measured as:
    11·1 answer
  • When should you use a piece of pipe as a leverage extension on the handle on a wrench?
    5·1 answer
  • In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best describes why the bell is
    6·1 answer
  • What is the force needed to throw a ball 7 meters when 1778 J of work is done?
    6·1 answer
  • With a pulley system, a force of only 50 lb can lift a 500-lb weight. What is the mechanical advantage if this system is 100% ef
    14·1 answer
  • Mr. Rudman drives his race car for 4 hrs at 150<br> miles/hr. How far will he travel?
    8·1 answer
  • What is the height of the Golden Bridge?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!