Waves<br> Please need help fast

Ice is put in a cooler to cool the contents. to speed up the cooling process, the ice can be?

QveST [7]

Crushing increases the ice's surface area. Additionally, cooling from ice happens as a result of convection, which is proportional to area. Thus, breaking up the ice expedites the cooling process.

<h3>What is cooling process?</h3>

When precise and consistent temperature control inside a process is necessary, this sort of cooling is used. Because they can offer cooling capacity independent of variations in the ambient temperature, heat load, and flow needs of the application, chillers are frequently employed to remove heat from a process.

It's important to properly regulate the heat load in many industrial operations. Different components of the whole application might need to be cooled.

Major locations for cooling include:

Direct product cooling

During the molding process, plastic

milling metal products

To know more about cooling process, visit;

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5 0

2 years ago

The Earth moves in predicable patterns. One of these patterns causes the seasons as

Rina8888 [55]

Answer:

A A A A A A A A

8 0

3 years ago

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g The steam above a freshly made cup of instant coffee is really water vapor droplets condensing after evaporating from the hot

geniusboy [140]

Answer:

the final temperature = 74.33°C

Explanation:

Using the expression Q = mcΔT for the heat transfer and the change in temperature .

Here ;

Q = heat transfer

m = mass of substance

c = specific heat

ΔT = the change in temperature

The heat Q required to change the phase of a sample mass m is:

Q = m $L_v$

where;

$L_v$ is the latent heat of vaporization.

From the question ;

Let M represent the mass of the coffee that remains after evaporation is:

ΔT = $\frac{mL_v}{MC}$

where;

m = 2.50 g

M = (240 - 2.50) g = 237.5 g

$L_v$ = 539 kcal/kg

c = 1.00kcal/kg. °C

ΔT = $\frac{2.50*539 \ kcal /kg}{237.5 g *1.00 \ kcal/kg . ^0C}$

ΔT = 5.67°C

The final temperature of the coffee is:

$T_f = T_i -$ ΔT

where ;

$T_I$ = initial temperature = 80 °C

$T_f$ = (80 - 5.67)°C

$T_f$ = 74.33°C

Thus; the final temperature = 74.33°C

8 0

3 years ago

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A ray moving in plastic at 62.9 deg enters water, where it bends to 70.9 deg. What is the index of refraction of the plastic?

DedPeter [7]

Answer:

refractive index of plastic is 1.42

Explanation:

When light ray enters from one medium to other medium then due to transition of light it bends away or towards the normal, this phenomenon is known as refraction of light

So here we know that

$n_1 sin i = n_2 sin r$

here we have

$n_2 = \frac{4}{3}$

$i = 62.9^o$

$r = 70.9^o$

now we have

$n_1 sin62.9 = (\frac{4}{3}) sin70.9$

$n_1 = 1.42$

7 0

3 years ago

Train cars are coupled together by being bumped into one another. Suppose two loaded cars are moving toward one another, the fir

tia_tia [17]

Answer:

7560 Joules

Explanation:

$m_1$ = Mass of first car = $1.5\times 10^5\ kg$

$m_2$ = Mass of second car = $2\times 10^5\ kg$

$u_1$ = Initial Velocity of first car = 0.3 m/s

$u_2$ = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

As linear momentum of the system is conserved

$m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{1.5\times 10^5\times 0.3 + 2\times 10^5\times -0.12}{1.5\times 10^5 + 2\times 10^5}\\\Rightarrow v=0.06\ m/s$

Energy lost is

$\Delta E=\Delta E_i-\Delta E_f\\\Rightarrow \Delta=\frac{1}{2}(m_1u_1^2 + m_2u_2^2-(m_1+m_2)v^2)\\\Rightarrow \Delta=\frac{1}{2}(1.5\times 10^5\times 0.3^2 + 2\times 10^5\times (-0.12)^2-(1.5\times 10^5 + 2\times 10^5)\times 0.06^2)\\\Rightarrow \Delta=7560\ J$

The Energy lost in the collision is 7560 Joules

7 0

3 years ago

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