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ch4aika [34]
1 year ago
12

Waves Please need help fast

Physics
1 answer:
mixas84 [53]1 year ago
6 0
I believe its the third answer
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The layer of earth that has the lightest elements is the
Sonja [21]
If I remember correctly (from my studies long time ago) the layers are from the outer to the center:
SiAl : Silicon-Aluminum
SiMa : Silicon-Magnesium (although should be Mg)
NiFe : Nickel-Iron

The SiMa layer should have the lightest elements (Magnesium is lighter than Aluminum)
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3 years ago
____ waves are often used in heat lamps fill in the blank
Ludmilka [50]
Heat your answer is Heat.

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Beer, an alcoholic beverage, is a solution composed primarily of water with an ethanol content of about 7%. identify the solute
zloy xaker [14]
Hi, thank you for posting your question here at Brainly.

A mixture primarily consists of the solute and the solvent. The solvent constitutes the majority of the amount in the mixture. Since ethanol account for 7%, then water must be 93%, considering other inert materials to be negligible.

Thus, the solute is ethanol and the solvent is water.
3 0
2 years ago
What is the mass moment of inertia of a 20kg sphere with a radius of 0.2m about a point on the sphere's perimeter
Kobotan [32]

Answer:

I = M R^2 is the moment of inertia about a point that is a distance R from the center of mass (uniform distributed mass).

The moment  of inertia about the center of a sphere is 2 / 5 M R^2.

By the parallel axis theorem the moment of inertia about a point on the rim of the sphere is  I = 2/5 M R^2 + M R^2 = 7/5 M R^2

I = 7/5 * 20 kg * .2^2 m = 1.12 kg m^2

7 0
2 years ago
How much ice (at 0°C) must be added to 1.90 kg of water at 79 °C so as to end up with all liquid at 8 °C? (ci = 2000 J/(kg.°
muminat

m = mass of the ice added = ?

M = mass of water = 1.90 kg

c_{w} = specific heat of the water = 4186 J/(kg ⁰C)

c_{i}  = specific heat of the ice = 2000 J/(kg ⁰C)

L_{f} = latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg

T_{ii}  = initial temperature of ice = 0 ⁰C

T_{wi} = initial temperature of water = 79 ⁰C

T = final equilibrium temperature = 8 ⁰C

using conservation of heat

Heat gained by ice = Heat lost by water

m c_{w}  (T - T_{ii} ) + m L_{f}  = M c_{w}  (T_{wi} - T)

inserting the values

m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)

m = 1.53 kg

4 0
3 years ago
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