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3 years ago

Help??????????????????????

Mathematics

1 answer:

antoniya [11.8K]3 years ago

4 0

Answer:

30°

Step-by-step explanation:

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Can someone please answer this and explain it?

professor190 [17]

Answer:

Velocity = displacement / time

Distance = 3t^2 +2t +6 to find distance you need to plug in time = 2 sec

Distance = 3(2)^2 +2(2) +6

Distance = 3(4) +4 + 6

Distance = 12 + 4 +6

Distance = 22 meters

In this problem the displacement is the distance.

Velocity = 22 meters / 2 second

Velocity = 11 meters/second

Does this help?

Step-by-step explanation:

4 0

3 years ago

HURRY PLZ

Oliga [24]

Answer:

6x + 2(−2x + 1) = 22

Step-by-step explanation:

6x + 2(−2x + 1) = 22

This step can be used to solve by substitution method.

8 0

3 years ago

(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13

jolli1 [7]

Answer:

$y(x)=3e^{5x}-2xe^{5x}$

Step-by-step explanation:

The given differential equation is $y''-10y'+25y=0$

The characteristics equation is given by

$r^2-10r+25=0$

Finding the values of r

$r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5$

We got a repeated roots. Hence, the solution of the differential equation is given by

$y(x)=c_1e^{5x}+c_2xe^{5x}...(i)$

On differentiating, we get

$y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)$

Apply the initial condition y (0)= 3 in equation (i)

$3=c_1e^{0}+0\\\\c_1=3$

Now, apply the initial condition y' (0)= 13 in equation (ii)

$13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2$

Therefore, the solution of the differential equation is

$y(x)=3e^{5x}-2xe^{5x}$

5 0

3 years ago

116,02 LC)

nadezda [96]

B. Triangle B and Triangle D
Triangle A has all equal sides and Triangle C is a right triangle.

5 0

3 years ago

Find f(x) - g(x) *

Studentka2010 [4]

Answer:

3x^3+13x^2-3x+7

Step-by-step explanation:

I dont know if your question is complete.

f(x) - g(x)

$(4x^3+6x^2-3x+9)-(x^3-7x^2+2)\\4x^3+6x^2-3x+9-x^3+7x^2-2\\3x^3+13x^2-3x+7$

6 0

2 years ago