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gayaneshka [121]
3 years ago
9

Choose the product. -6p3(3p2 + 5p - 1) -18p5 - 30p4 + 6p3 -18p6 - 30p3 - 6p 18p3 + 6p2 - 30p4 -18p6 - 24p3

Mathematics
1 answer:
wlad13 [49]3 years ago
7 0
-6p^3(3p^2 +5p -1) = -18p^5 -30p^4 +6p^3

so this is the right answer sure 
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Answer:

The possible rational roots are: +1, -1 ,+3, -3, +9, -9

Step-by-step explanation:

The Rational Root Theorem tells us that the possible rational roots of the polynomial are given by all possible quotients formed by factors of the constant term of the polynomial (usually listed as last when written in standard form), divided by possible factors of the polynomial's leading coefficient. And also that we need to consider both the positive and negative forms of such quotients.

So we start noticing that since the leading term of this polynomial is x^3, the leading coefficient is "1", and therefore the list of factors for this is: +1, -1

On the other hand, the constant term of the polynomial is "9", and therefore its factors to consider are: +1, -1 ,+3, -3, +9, -9

Then the quotient of possible factors of the constant term, divided by possible factor of the leading coefficient gives us:

+1, -1 ,+3, -3, +9, -9

And therefore, this is the list of possible roots of the polynomial.

6 0
3 years ago
If a sample of 362 customers is taken from a population of 5530 customers,
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Using concepts of <u>sample and population</u>, it is found that the sample variance is representative of 362 and 5530 customers ages, option D.

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In sampling, the <u>information is taken from a sample</u>, and is used to <u>estimate it for the whole population</u>.

  • In this problem, we have a sample of 362 and a population of 5530 customers.
  • The sample variance s^2 is calculated from the sample, and used as an estimate for the population variance. Thus, it can be said that it represents both 362 and 5530 customers, and the correct option is D.

A similar problem is given at brainly.com/question/4086221

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True, In Euclidean geometry an equilateral triangle must be a 60-60-60 triangle.

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