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kifflom [539]
3 years ago
9

A hydrated sample weighing 20.0 g is heated in a crucible at 250°C. After cooling the sample now has a weight of 16.5 g.

Chemistry
1 answer:
anzhelika [568]3 years ago
8 0

Given parameters:

Weight of hydrated sample  = 20g

Temperature = 250°C

Weight after cooling  = 16.5g

Unknown:

Weight of water lost from the sample = ?

Solution:

The weight of water lost from the sample;

    Weight of water lost = Weight of hydrated sample - Weight of dry sample

    Weight of water lost = 20g - 16.5g  = 3.5g

% of water in the sample = \frac{mass of water}{mass of original sample}  x 100

  Input parameters solve;

                              = \frac{3.5}{20}  x 100

                               =17.5%

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2. is a physical change.  The salt is breaking up into ions but is still there.  if you evaporate the water, the salt appears again (you can think of dissolving as a change in state in a way).

3.  chemical change.  The water is being broken up into oxygen and hydrogen indicating a chemical reaction. (this reaction is called electrolysis).

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