Kind of this is probably wrong Mass weight of solid, volume weight of liquid?
Answer:
2.52 atm
Explanation:
Change C to K.
Solve for P1=P2V2T2/V1T1
- Hope that helps! Please let me know if you need further explanation.
Using the Equation: PV=nRT
Where P is the pressure 60 cmHg or 600 mmHg or 600/760= 0.789 atm
V is the volume 125 ml or 0.125 L, n is the number of moles, R is a constant 0.082057, and T is temperature 25 °C or 298 K;
Therefore:
0.789 × 0.125 = n × 0.082057 × 298
n = 0.0987/24.45
= 0.004036 mol
0.004036 mole has a mass of 0.286 g
Hence; 1 mole has a mass of 0.286/0.004036
= 70.8 g /mol
Therefore the molar mass of the gas is 71 g/mol (2 sfg)
Ga₂O₃ + 2NaOH + 3H₂O = 2Na[Ga(OH)₄]
[Ga(OH)]⁻ + 3e⁻ = Ga + 4OH⁻
n(Ga)=It/(zF)
I=0.200 A
t=40.0 min=2400 s
z=3
F=96485.33 Kl/mol
n(Ga)=0.200*2400/(3*96485.33)=0.00166 =1.66*10⁻³ mol