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faltersainse [42]
4 years ago
8

Under what conditions will a gas be most likely to exhibit the ideal gas properties predicted by the ideal gas law?

Chemistry
1 answer:
klasskru [66]4 years ago
3 0

Answer:

3) Low pressure and high temperature, because particles are spread farther apart and moving faster, so the intermolecular forces of attraction are weaker

Explanation:

Please mark brainliest and have a great day!

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What is the process used to convert between moles, mass, volume, and particles?
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conversion between mass and moles#

<em> </em>

<em>A substance's molar mass is calculated by multiplying its relative atomic mass by the molar mass constant (1 g/mol). The molar mass constant can be used to convert mass to moles. By multiplying a given mass by the molar mass, the amount of moles of the substance can be calculated.</em>

<em> </em>

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2 years ago
How many atoms are in 15.0 moles of C2H6O
Burka [1]
1 mole = 6.22 x 10^23 molecules (Avogadro's number)
15 moles x (6.22 x 10^23) = 9.33 x 10^24 atoms
3 0
4 years ago
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What is mass per unit volume called?
harina [27]

Answer:

The correct answer is Density

Explanation:

Hope this helps you

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3 years ago
Which substance is used to remove rust from metal
wel
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3 0
3 years ago
Read 2 more answers
The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

m \approx \dfrac{53.3}{6.021}

\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

3 0
3 years ago
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