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AveGali [126]
3 years ago
10

Evaluate BC for A = 5, B = -4, and C = 2. 6. -6 -8

Mathematics
1 answer:
tamaranim1 [39]3 years ago
7 0

Answer:

-8

Step-by-step explanation:

we have from the statement:

BC

B = -4

C = 2.

we need to multiply B and C

B*C=(-4)*(2)

we have

B*C=-8

The answer is -8

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Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

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OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

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Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

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tan(∠NMQ) = \frac{NQ}{QM}

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⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

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Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

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       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

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