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Basile [38]
3 years ago
8

The bear was chosen

Mathematics
1 answer:
cestrela7 [59]3 years ago
6 0

Answer:

it was chosen 9 more times

Step-by-step explanation: i had this on my quiz

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7x+5+ 54 how you do this
KonstantinChe [14]

Answer:

7x+59

Step-by-step explanation:

Add 5 and 54

3 0
3 years ago
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Create and answer your
shutvik [7]

Step-by-step explanation:

\frac{20}{48}  \times  \frac{80}{44}

Divide the fraction with 4

\frac{20÷4}{48÷4} \times \frac{80÷4}{44÷4} = \frac{5}{12}  \times  \frac{20}{11}

Reduce the number with factor 4

\frac{5}{12÷4} \times \frac{20÷4}{11} = \frac{5}{3}   \times  \frac{5}{11}

Multiply the fractions

\frac{5 \times 5}{3 \times 11}  =  \frac{25}{33}

\boxed{\green{=  \frac{25}{33}  = 0.75}}

7 0
2 years ago
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Tan(x+pi/2)= negative cot x
DIA [1.3K]
I'm only going to alter the left hand side. The right side will stay the same the entire time

I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)

So with that in mind, this is how the steps would look:

tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x

Identity is confirmed

6 0
3 years ago
How would i number the graph
tiny-mole [99]
Put numbers up and down the X and Y axis showing what the graph values are. (Ex: see picture ) make sure you do it accurately based on what the slope will look like.

8 0
3 years ago
James wants to invest $12,000. He can invest the money at 7.2% simple interest for 30 yr or he can invest at 6.8% with interest
Sever21 [200]

Over time, compound interest at any rate will outperform simple interest. When the rates are nearly equal to start with, compound interest will be greater in very short order. Here, it takes less than 1 year for compound interest to give a larger account balance.

In 30 years, the simple interest will be

... I = P·r·t = 12,000·0.07·30 = 25,200

In 30 years, the compound interest will be

... I = P·(e^(rt) -1) = 12,000·(e^(.068·30) -1) ≈ 80,287.31

_____

6.8% compounded continuously results in more total interest

4 0
2 years ago
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