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MaRussiya [10]
4 years ago
14

Please help on 13 and 14

Mathematics
1 answer:
alexira [117]4 years ago
4 0

Answer:

13) The planes ABF and FHG are  perpendicular

14)  Segments Ab and CD are parallel.

Step-by-step explanation:

13)

Planes ABF and FHG are perpendicular (they intersect along side EF)

14)

In order to find out about the segments AB and CD, let's use the formula for the slope that joins any two points (x_1,y_1)\,\,\&\,\,(x_2,y_2) on the plane:

slope=\frac{y_2-y_1}{x_2-x_1}

Therefore, given:

A = (-3, 2)

B = (1, 4)

C = (-3, -1)

D = (1, 1)

we have for segment AB the following slope:

slope_{AB}=\frac{4-2}{1+3} =\frac{2}{4} =\frac{1}{2}

and for segment CD the following slope:

slope_{CD}=\frac{1+1}{1+3} =\frac{2}{4} =\frac{1}{2}

Since they show the same slope, these two segments are parallel.

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Divide £80 in the ratio 1:4:5​
yarga [219]

Answer:

8, 32, and 40

Step-by-step explanation:

1+4+5=10

80/10=8

8*1=8

8*4=32

8*5=40

3 0
4 years ago
Write 35.2 in a word form
Brilliant_brown [7]
35.2 in word form is: Thirty Five and 2 Tenths.
HOPE I HELPED!!!
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7 0
4 years ago
Read 2 more answers
Solve this system of linear equations. Separate the x- and y- values with a coma. 3x=36-15y. 11x =-78+15y
Brrunno [24]

Answer:

(-3,3)

Step-by-step explanation:

3x=36-15y and 11x =-78+15y

We move all x  and y terms to the left hand side of the equation , so that we can apply elimination method

3x=36-15y , Add 15 y on both sides , 3x + 15y = 36

11x =-78+15y, subtract 15y on both sides, 11x -15y = -78

Now we add both equations

3x  + 15y = 36

11x -15y = -78

------------------------

14x  = -42

divide both sides by 14

x= -3

Now Plug in -3 for x in any one of the given equation

3x=36-15y

3(-3) = 36 - 15y

-9 = 36 - 15y

Subtract 36 on both sides

-45 = -15y

Divide both sides by -15

So y= 3

Answer is (-3,3)

5 0
3 years ago
I don’t understand the polynomials
Serhud [2]
Polynomial comes from poly- (meaning "many") and -nomial (in this case meaning "term") ... so it says "many terms"

A polynomial can have:

constants (like 3, −20, or ½)
variables (like x and y)
exponents (like the 2 in y2), but only 0, 1, 2, 3, ... etc are allowed
that can be combined using addition, subtraction, multiplication and division ...

... except ...

... not division by a variable (so something like 2/x is right out)

So:

A polynomial can have constants, variables and exponents,
but never division by a variable.

Also they can have one or more terms, but not an infinite number of terms.

These are polynomials:

3x
x − 2
−6y2 − ( 79 )x
3xyz + 3xy2z − 0.1xz − 200y + 0.5
512v5 + 99w5
5
(Yes, "5" is a polynomial, one term is allowed, and it can be just a constant!)



These are not polynomials

3xy-2 is not, because the exponent is "-2" (exponents can only be 0,1,2,...)
2/(x+2) is not, because dividing by a variable is not allowed
1/x is not either
√x is not, because the exponent is "½" (see fractional exponents)


But these are allowed:

x/2 is allowed, because you can divide by a constant
also 3x/8 for the same reason
√2 is allowed, because it is a constant (= 1.4142...etc)
7 0
3 years ago
9+(-2)x3=7x3 DONT forget pemdas or gemdas
gizmo_the_mogwai [7]

Answer:

The equation is true.

Step-by-step explanation:

First you divide both sides of the equation by 3. This leaves you with 9-2=7 (notice I rewrote 9+(-2) to 9-2, this is because they mean the same thing one is just easier to look at). Then you add 2 to both sides. This cancels the 2 on the left side and makes the rights side a nine. Since both sides leave you with nine this proves are equal, making it a true equation.

6 0
4 years ago
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