Answer:
A
Step-by-step explanation:
pls mark brainliest
Answer:
(x +2)(2x +1)
Step-by-step explanation:
The factors are the set of tiles down the left side: x + 1 + 1 = (x +2), and the set of tiles across the top: x + x + 1 = (2x +1)
Your factored form is shown in choice D:
(x +2)(2x +1)
_____
<em>Additional comment</em>
The point of this sort of diagram is to show you how the factors work together to give you the product. Each tile in the middle of the figure represents the product of the tile on the top line and the tile in the left column.
The product of x and x is x².
The product of 1 and x is x.
The product of 1 and 1 is 1.
The product of the two factors is the sum of all the tiles in the middle of the diagram: 2x² +5x +2.
Answer:
1. ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y)
2. ∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)
Step-by-step explanation:
If we negate a quantified statement, first we negate all the quantifiers in the statement from left to right, ( keeping the same order ) then we negative the statement,
Here, the given statement,
1. ∃y ∈Z such that ∀x ∈Z, R (x + y)
By the above definition,
Negation of this statement is ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y),
2. Similarly,
The negation of statement ∀x ∈Z, ∃y∈Z such that R(x + y),
∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)
Answer:
(x + 6)² + 16 = 0
Step-by-step explanation:
To complete the square we will first need to get our equation to look like: x² + bx = c
Here we have x² + bx + c = 0 → x² + 12x + 52 = 0
- First we need to subtract our c, in this case 52, from both sides to get x² + 12x = -52
- We then need to add
to both sides of the equation - Here our b value is 12, so plugging this into our formula we get
- Adding 36 to both sides our equation becomes: x² + 12x + 36 = -52 + 36
- Then combining like terms on the right side we get x² + 12x + 36 = -16
- Now making our left side of the equation into a perfect square we get: (x + 6)² = -16
- Finally adding the 16 to both sides of the equation we get: (x + 6)² + 16 = 0
Answer:
hodrvyeieiwb was the only one to win a lot