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MaRussiya [10]
3 years ago
14

Please help on 13 and 14

Mathematics
1 answer:
alexira [117]3 years ago
4 0

Answer:

13) The planes ABF and FHG are  perpendicular

14)  Segments Ab and CD are parallel.

Step-by-step explanation:

13)

Planes ABF and FHG are perpendicular (they intersect along side EF)

14)

In order to find out about the segments AB and CD, let's use the formula for the slope that joins any two points (x_1,y_1)\,\,\&\,\,(x_2,y_2) on the plane:

slope=\frac{y_2-y_1}{x_2-x_1}

Therefore, given:

A = (-3, 2)

B = (1, 4)

C = (-3, -1)

D = (1, 1)

we have for segment AB the following slope:

slope_{AB}=\frac{4-2}{1+3} =\frac{2}{4} =\frac{1}{2}

and for segment CD the following slope:

slope_{CD}=\frac{1+1}{1+3} =\frac{2}{4} =\frac{1}{2}

Since they show the same slope, these two segments are parallel.

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Answer:

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Step-by-step explanation:

The factors are the set of tiles down the left side: x + 1 + 1 = (x +2), and the set of tiles across the top: x + x + 1 = (2x +1)

Your factored form is shown in choice D:

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<em>Additional comment</em>

The point of this sort of diagram is to show you how the factors work together to give you the product. Each tile in the middle of the figure represents the product of the tile on the top line and the tile in the left column.

The product of x and x is x².

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3 0
2 years ago
Write down the negation of each statement
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Answer:

1. ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y)

2. ∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)

Step-by-step explanation:

If we negate a quantified statement, first we negate all the quantifiers in the statement from left to right, ( keeping the same order ) then we negative the statement,

Here, the given statement,

1. ∃y ∈Z such that ∀x ∈Z, R (x + y)

By the above definition,

Negation of this statement is ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y),

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∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)

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Solve the quadratic equation by completing the square.<br> x^2+12x+52=0
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Answer:

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Step-by-step explanation:

To complete the square we will first need to get our equation to look like: x² + bx = c

Here we have x² + bx + c = 0 → x² + 12x + 52 = 0

  • First we need to subtract our c, in this case 52, from both sides to get x² + 12x = -52
  • We then need to add (\frac{b}{2} )^{2} to both sides of the equation
  • Here our b value is 12, so plugging this into our formula we get (\frac{12}{2} )^{2} =(6)^{2} =36
  • Adding 36 to both sides our equation becomes: x² + 12x + 36 = -52 + 36
  • Then combining like terms on the right side we get x² + 12x + 36 = -16
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