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1 year ago

Please help 100 points please

Mathematics

1 answer:

Schach [20]1 year ago

4 0

Solution:

We know that:

Area of trapezoid = (a₁ + a₂)h/2
a₁ = 8 inches; a₂ = 8 + 4 + 4 inches; Height = 6 in.

This means that:

Area of trapezoid = (8 + 8 + 4 + 4)6/2

Step-by step calculations:

Simplify the numerator:

Area of trapezoid = (8 + 8 + 4 + 4)6/2
=> Area of trapezoid = (24)6/2

Cancel the denominator:

=> Area of trapezoid = (24)3

Simplify the term:

=> Area of trapezoid = 72 in²

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Answer:

See explanation

Step-by-step explanation:

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Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

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8x+5y=-20

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