4 years ago

Help me please thank you

Mathematics

1 answer:

Lapatulllka [165]4 years ago

3 0

All of them except TR and PH

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Simplify completely.

Arte-miy333 [17]

Answer:

$\large\boxed{\sqrt{27y^8}=3y^4\sqrt3}$

Step-by-step explanation:

$\sqrt{27y^8}=\sqrt{9\cdot3\cdot y^{4\cdot2}}\\\\\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b},\ (a^n)^m=a^{nm}\ \text{and}\ \sqrt{a^2}=a\\\\=\sqrt9\cdot\sqrt3\cdot\sqrt{(y^4)^2}=3\cdot\sqrt3\cdot y^4=3y^4\sqrt3$

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3 years ago

Find the area of a circle with a diameter of 10 units. Round answer to the nearest hundredth of a square unit.

Misha Larkins [42]

Answer:

Step-by-step explanation:

The area of a circle is given by A = π*r²

If diameter is 10 units, the radius is 5, so:

A = π * 5² = 78,54units²

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4 years ago

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Ostrovityanka [42]

54-10 ≥ 20+7x
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3 years ago

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kumpel [21]

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Step-by-step explanation:

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Murrr4er [49]

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Step-by-step explanation:

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