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3 years ago

Simplify completely.

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer:

$\large\boxed{\sqrt{27y^8}=3y^4\sqrt3}$

Step-by-step explanation:

$\sqrt{27y^8}=\sqrt{9\cdot3\cdot y^{4\cdot2}}\\\\\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b},\ (a^n)^m=a^{nm}\ \text{and}\ \sqrt{a^2}=a\\\\=\sqrt9\cdot\sqrt3\cdot\sqrt{(y^4)^2}=3\cdot\sqrt3\cdot y^4=3y^4\sqrt3$

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Answer:

5.54 inches of rain

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

Given

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3 years ago

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nataly862011 [7]

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3 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

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3 years ago

A flat rectangular piece of aluminum has a perimeter of 62 inches. The length is 15

Salsk061 [2.6K]

Answer:

So, the required width of rectangular piece of aluminium is 8 inches

Step-by-step explanation:

We are given:

Perimeter of rectangular piece of aluminium = 62 inches

Let width of rectangular piece of aluminium = w

and length of rectangular piece of aluminium = w+15

We need to find width i.e value of x

The formula for finding perimeter of rectangle is: $Perimeter=2(Length+Width)\\$

Now, Putting values in formula for finding Width w:

$Perimeter=2(Length+Width)\\\\62=2(w+15+w)\\62=2(2w+15)\\62=4w+30\\62-30=4w\\4w=32\\w=\frac{32}{4}\\w=8$

After solving we get the width of rectangular piece :w = 8

So, the required width of rectangular piece of aluminium is 8 inches

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3 years ago