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3 years ago

Simplify completely.

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer:

$\large\boxed{\sqrt{27y^8}=3y^4\sqrt3}$

Step-by-step explanation:

$\sqrt{27y^8}=\sqrt{9\cdot3\cdot y^{4\cdot2}}\\\\\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b},\ (a^n)^m=a^{nm}\ \text{and}\ \sqrt{a^2}=a\\\\=\sqrt9\cdot\sqrt3\cdot\sqrt{(y^4)^2}=3\cdot\sqrt3\cdot y^4=3y^4\sqrt3$

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