158 divided by 37 I don’t get it what is the answer
2 answers:
Answer:
4.2702702703
=
4 Remainder 10
Step-by-step explanation:
158 divided by 37 = 4.270
The result of 158/37 is a non-terminating, repeating decimal.
The repeating pattern above, 270, is called repetend, and denoted overlined with a vinculum.
This notation in parentheses is also common: 158/37 = 4.(270): However, in daily use it’s likely you come across the reptend indicated as ellipsis: 158 / 37 = 4.270… .
158 divided by 37 in decimal = 4.270
158 divided by 37 in fraction = 158/37
158 divided by 37 in percentage = 427.02702703%
Note that you may use our state-of-the-art calculator above to obtain the quotient of any two integers or decimals, including 158 and 37, of course.
Repetends, if any, are denoted in ().
The conversion is done automatically once the nominator, e.g. 158, and the denominator, e.g. 37, have been inserted.
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Answer:
S = {(0, 5), (0, - 5), (3, 4), (3, -4), (-3, 4), (-3, -4), (4, 3), (4, -3), (-4, 3), (-4, -3), (5,0), (-5, 0) }
Step-by-step explanation:
Remember that the distance between two points (a, b) and (c, d) is given by:
So, here we have that the distance between the point (x, y) and the origin, (0, 0) must have a magnitude of 5 units, then we want to solve:
If we square both sides, we get
Now we want to find all the points (x, y) that meet this condition, suc that:
x ∈ Z
y ∈ Z
So both x and y must be integers.
So here we can just play with different values of x and y.
For example, if we define:
x = 0 we get:
25 = 0^2 + y^2
25 = y^2
√25 = y
Then we can have y = 5 or y = -5
from this we got two points:
(0, 5) and (0, - 5)
if x = 1 we have:
25 = 1^2 + y^2
25 - 1 = y^2
24 = y^2
There is no integer such that its square is equal to 24, so we can stop here.
if x = 2 or - 2, we have:
25 = 2^2 + y^2
25 = 4 + y^2
25 -4 = 21 = y^2
Again, there is no integer such that its square is equal to 21, so we can stop here.
if x = +3 or -3, we have:
25 = 3^2 + y^2
25 = 9 + y^2
25 - 9 = 16 = y^2
√16 = y
then we can have y = 4 or y = -4
from this we got four points:
(3, 4)
(-3, 4)
(3, -4)
(-3, -4)
And for symmetry, if x = 4 or -4 we have the points:
(-4, 3)
(4, 3)
(-4, -3)
(4, -3)
finally, again for symmetry, if we take x = 5 or x = -5 we have the points:
(5,0)
(-5, 0)
Concluding, the set of all possible values (x, y) is:
S = {(0, 5), (0, - 5), (3, 4), (3, -4), (-3, 4), (-3, -4), (4, 3), (4, -3), (-4, 3), (-4, -3), (5,0), (-5, 0) }