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Alika [10]
3 years ago
15

158 divided by 37 I don’t get it what is the answer

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0

Answer:

4.2702702703

=

4 Remainder 10

Step-by-step explanation:

158 divided by 37 = 4.270

The result of 158/37 is a non-terminating, repeating decimal.

The repeating pattern above, 270, is called repetend, and denoted overlined with a vinculum.

This notation in parentheses is also common: 158/37 = 4.(270): However, in daily use it’s likely you come across the reptend indicated as ellipsis: 158 / 37 = 4.270… .

158 divided by 37 in decimal = 4.270

158 divided by 37 in fraction = 158/37

158 divided by 37 in percentage = 427.02702703%

Note that you may use our state-of-the-art calculator above to obtain the quotient of any two integers or decimals, including 158 and 37, of course.

Repetends, if any, are denoted in ().

The conversion is done automatically once the nominator, e.g. 158, and the denominator, e.g. 37, have been inserted.  

vredina [299]3 years ago
5 0

Answer:

4.2703

Step-by-step explanation:

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According to the histogram, how many students live between 2 and 2.9 miles
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Step-by-step explanation:

7 0
4 years ago
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I need to solve this system of equations, how do I do that?<br> 3x-4y=20<br> y=3/4x-5
Paha777 [63]

Answer:

Is is Infinitely many solutions so 0=0

<em><u>Step-by-step explanation:</u></em>

<h3>First we have to rearrange/simplify the equations:</h3>

Equation 1: 4y - 3x = -20

Equation (2):  y - 3x/4  = -5

<h3>Then you remove the fractions by multiplication: </h3>

Multiply equation (2) by 4

<h3>The Equations now look like this: </h3>

Equation 1: 4y - 3x = -20

Equation (2): 4y - 3x = -20

<h3>Solve for y on Equation (2):</h3>

y = <u><em>3x/4 - 5</em></u>

<h3>Then plug in this for the y in Equation 1 and then solve:</h3>

4•(<u><em>3x/4-5</em></u>) - 3x = -20

Therefore the answer leads to:

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Hope this helped :')

4 0
3 years ago
Solve for y.<br> -5y+6=-12y+62
Dmitrij [34]

Answer:

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Step-by-step explanation:

Add 12y to both sides

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y=8

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4 0
3 years ago
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