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tekilochka [14]
3 years ago
9

Given f(x)=x-5/3 solve for f^-1(3)

Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0
F^-1(x)=3/x+5 I’m pretty sure this it it
iren2701 [21]3 years ago
7 0
F(x)=x-5/3 you have to put the 3 everywhere x is
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Please help me and show your work!!
11Alexandr11 [23.1K]
\bf \cfrac{\sqrt{250x^{16}}}{\sqrt{2x}}\qquad 
\begin{cases}
250=2\cdot 5\cdot 5\cdot 5\\
\qquad 2\cdot 5\cdot 5^2\\
x^{16}=x^{8\cdot 2}\\
\qquad (x^8)^2
\end{cases}\implies \cfrac{\sqrt{2\cdot 5\cdot 5^2\cdot (x^8)^2}}{\sqrt{2\cdot  x}}

\bf \cfrac{5x^8\sqrt{2\cdot 5}}{\sqrt{2}\cdot \sqrt{x}}\implies \cfrac{5x^8\underline{\sqrt{2}}\cdot \sqrt{5}}{\underline{\sqrt{2}}\cdot \sqrt{x}}\implies \cfrac{5x^8\sqrt{5}}{\sqrt{x}}\impliedby 
\begin{array}{llll}
\textit{and rationalizing the}\\
\textit{denominator}
\end{array}

\bf \cfrac{5x^8\sqrt{5}}{\sqrt{x}}\cdot \cfrac{\sqrt{x}}{\sqrt{x}}\implies \cfrac{5x^8\sqrt{5}\cdot \sqrt{x}}{(\sqrt{x})^2}\implies \cfrac{5x^8\sqrt{5x}}{x}\implies 5x^8x^{-1}\sqrt{5x}
\\\\\\
5x^{8-1}\sqrt{5x}\implies 5x^7\sqrt{5x}
4 0
3 years ago
A puppy named Scout started out at 3 pounds and gained 1 pound every month. How heavy was Scout at 6 months old?
icang [17]

Answer:

9 pounds

Step-by-step explanation:

1 pound × 6 months =6 pounds

then add the 3 pounds Scout started with

6 + 3 =9

Scout is 9 pounds

hoped i help :)

8 0
3 years ago
OMG PLEASE HELP ME THIS IS HOMEWORK AND I NEED IT DONE OR I CANT GRADUATE TO HIGH SCHOOL
Dmitriy789 [7]
Other answers are coming soon :)

4 0
3 years ago
Beaker A contains 1 liter which is 15 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which
Tanzania [10]

Answer:

Add 1.25 litres of oil.

Step-by-step explanation:

Contents in beaker A implies;

15% of oil in 1 litre = 0.15 litres of oil

So that, there are 0.15 litres of oil and 0.85 litres of vinegar in beaker A.

Contents in beaker B implies:

55% of oil in 2 litres = 1.1 litres of oil

So that, thee are 1.1 litres of oil and 0.9 litres of vinegar in beaker B.

Half of contents of B poured into A implies that beaker A now contains:

0.15 litres + 0.55 litres = 0.7 litres of oil

0.85 litres + 0.45 litres = 1.3 litres of vinegar

The percentage of oil in A now = \frac{0.7}{2} x 100%

                                                    = 35%

To increase the percentage of oil to 60%, then:

0.7 litres + 1.25 litres = 1.95 litres of oil

But the new total litres of the content in beaker A = 3.25 litres

So that;

\frac{1.95}{3.25} x 100% = 60%

Therefore, to produce a mixture which is 60% oil, add 1.25 litres of oil.

7 0
3 years ago
Which describes 9 and -9?
Stolb23 [73]
What error!!!!! Bbbbbbb
3 0
3 years ago
Read 2 more answers
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