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lara [203]
3 years ago
5

For circle A, A F = AG, A F is perpendicular to CD, and AG is perpendicular to EB. What conclusion can be made? a circle with ce

nter A and chords CD and EB
a segment from A to chord CD intersects chord CD at F, and a segment from A to chord EB intersects chord EB at G segment CD is parallel to segment EB segment CD is congruent to segment EB segment A F is perpendicular to segment AG segment CF is congruent to segment A F
Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

cd is congruent to eb

Step-by-step explanation:

maks197457 [2]3 years ago
6 0

Answer:

segment CD is congruent to segment EB

Step-by-step explanation:

it was right on my test

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Answer/Step-by-step explanation:

1. Given:

m<ABC = 4x°,

m<BCD = 3x°,

m<CDA = 2x°,

m<DAB = 3x°

Sum of quadrilateral = (n - 2)180

Quadrilateral has 4 sides, therefore, n = 4.

Sum of quadrilateral = (4 - 2)180 = 2*180 = 360°

Equation to solve for x would be:

m<ABC + m<BCD + m<CDA + m<DAB = 360

Substituting the given expression for each angle, we have:

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m<ABC = 4x = 4*30 = 120°

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