You dived 4,005/16
then you will get your answer
Answer:
the answer is -32t + 67
Step-by-step explanation:
-16t2 +64 + 3
= -16t x 2 +64 +3
= -32t +67
I would answer, but you didn't give any options.
Y=Mx +c
M gradient so count how many squares per one line
C = y intercept (7.5) here it looks
Just sub in those
We know that the point is in Q II. Thus, the x-coordinate of this point will be negative and the y-coordinate will be positive.
The y-coordinate is essentially given, and is y=4.
Imagine drawing a vertical line thru x=-2. This line will intersect y=4 at (-2,4).
The coordinates of the point are (-2, -4).
