Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
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Answer:
The answer is the first one. Inside the absolute value symbols it is negative but absolute value answers are always positive. Instead of -30 the answer is 30.
Answer:
130.
Step-by-step explanation:
18 + 4(28(
= 18 + 4 * 28 Multiplication is done before addition so we have:
18 + 112
= 130.
