means to say that for any given 
, we can find 
such that anytime 
(i.e. the whenever 
is "close enough" to 5), we can guarantee that 
(i.e. the value of 
is "close enough" to the limit value).
What we want to end up with is
Dividing both sides by 3 gives
which suggests 
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let be given. Then if
and so the limit is 7. QED
Answer:
i can hardly see the data but from what i can see, maybe a bar graph
Step-by-step explanation:
1.
Seven hundred twenty-five
2.
Two hundred thirteen
Answer:
that help
Step-by-step explanation:
10h+27+−27=c+−27
10h=c−27
10h10=c−2710
h=110c+−2710
Answer:
h=110c+−2710
Answer:
1; -11+ 26 =15
2: 2- (-3) =5
3: 10+ (-4) = 7
4: 11 + -8 =3
5: -2 + 3 =1
6: 8 - 12 = -4
Step-by-step explanation:
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