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Tamiku [17]
4 years ago
13

(( I will give 20 points and brainy for right answers (Please answer all!!) CORRECTLY!!))

Mathematics
1 answer:
Gekata [30.6K]4 years ago
4 0
Problem 1.
Think of the outer rectangle by joining the two 5 in. sides with a segment.
Now you have an outer blue rectangle with a white rectangle missing.
For the outer rectangle:
The top and bottom sides measure 28 in.
The left and right sides measure 5 in. + 12 in. + 5 in. = 22 in.
Area of the outer rectangle = LW = 28 in. * 22 in. = 616 in.^2
Now look at the white square. You need to subtract this area from the outer rectangle.
area of white rectangle = LW = 12 in. * 15 in. = 180 in.^2

Subtract the areas:
616 in.^2 - 180 in.^2 = 436 in.^2

Answer:
<span>A. 436 Square Inches

Problem 2.
Do the same thing as for problem 1. Join the two 4 in. segments with a line.
</span>
<span>Think of the outer rectangle by joining the two 4 in. sides with a segment.
Now you have an outer blue rectangle with a white rectangle missing.
For the outer rectangle:
The top and bottom sides measure 24 in.
The left and right sides measure 4 in. + 12 in. + 4 in. = 20 in.
Area of the outer rectangle = LW = 24 in. * 20 in. = 480 in.^2
Now look at the white square. You need to subtract this area from the outer rectangle.
area of white rectangle = LW = 12 in. * 13 in. = 156 in.^2

Subtract the areas:
480 in.^2 - 156 in.^2 = 324 in.^2

Answer:
</span><span>B. 324 Square Inches</span>
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