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Hatshy [7]
3 years ago
10

The Base Ten Chart is a System of Units. Select the statement that is true. O The Units of each column can increase or decrease

20 times. Each unit column on the Base Ten Chart has a value. The value of the Unit column to the left of any given unit column is always 10 times greater and the value of the Unit column to the right is always 10 times less. O All unit columns are greater than the column to their left. O All unit columns are less than the unit column to their right.​
Mathematics
1 answer:
mr_godi [17]3 years ago
3 0
Each unit column on the Base Ten Chart has a value. The value of the Unit column to the left of any given unit column is always 10 times greater and the value of the Unit column to the right is always 10 times less.
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Answer:

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Answer:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

df = n-1= 22-1=21

t_{\alpha/2}= -2.08

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Step-by-step explanation:

Data given

\bar X=33.9 represent the sample mean

s=4.1 represent the sample standard deviation

n=22 sample size  

\mu_o =26 represent the value that we want to test

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:  

Null hypothesis:\mu \geq 36  

Alternative hypothesis:\mu < 36  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

Now we can calculate the critical value but first we need to find the degreed of freedom:

df = n-1= 22-1=21

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

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