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Bess [88]
3 years ago
5

What is 28% of 140? x = [?] : 140

Mathematics
2 answers:
MaRussiya [10]3 years ago
5 0

Answer:

28% of 140

28%×140

28/100×140

0.28×140

=39.2

maksim [4K]3 years ago
4 0
I got 39.2 as well. I calculated it.
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8-35. Use your knowledge of polygons to answer the questions below, if possible.
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Answer:

(a)I. 13 Sides II. 7 Sides

(b) 4 Sides, Square

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(a)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

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Then:

(n-2)180^0=1980^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=11\\$Add 2 to both sides of the equation\\n-2+2=11+2\\n=13

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Then:

(n-2)180^0=900^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=5\\$Add 2 to both sides of the equation\\n-2+2=5+2\\n=7

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(b)The sum of the exterior angle of a polygon is 360 degrees,

Each exterior angle of a n-sided regular polygon is: \frac{360^0}{n}

If the exterior angle of a regular polygon is 90°

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<u>(c)</u>The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

Each Interior angle of a regular n-sided polygon is:  \frac{(n-2)180^0}{n}

For a pentagon, n=5

Then:

\frac{(5-2)180^0}{5}=2x+4\\108=2x+4\\108-4=2x\\104=2x\\x=52^0

(d)The <u>sum of the exterior angle of a polygon is 360 degrees.</u>

If four of the exterior angles of a pentagon are 57, 74, 56, and 66.

Let the fifth angle=x

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57+74+56+66+x=360^0\\253+x=360\\x=107^0

(e)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

In an 11-gon., n=11

Therefore, the sum of the interior angle=(11-2)180=1620^0

The sum of the interior angle <u>does not change either in a regular or irregular polygon.</u>

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