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Soloha48 [4]
3 years ago
8

Plz help me with the answer

Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

<h2>y = 4</h2>

Step-by-step explanation:

Put x = 9 to the equation 3x + 4y = 43

(3)(9) + 4y = 43

27 + 4y = 43            <em>subtract 27 from both sides</em>

4y = 16            <em>divide both sides by 4</em>

y = 4

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Find the value of angle x ​<br><br><br><br>pls answer
Fiesta28 [93]

Answer:

110

Step-by-step explanation:

lets assume y is the angle next to x which should complete to form a 360.

50 + 25 + 35 + y = 360

y = 250

x + y = 360

x + 250 = 360

x = 110

5 0
2 years ago
Read 2 more answers
The diagonal of a TV screen is 26 inches. The screen is 18.8 inches wide. How high is the screen? Round to the nearest hundredth
cluponka [151]
26^2 = 18.8^2 + H^2
H^2 = 322.56
H = 17.96 inches
8 0
3 years ago
suppose a parabola has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1). Write the eq
lesya [120]

Answer:

<h3>            f(x) = - 3(x + 8)² + 2</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k   - the vertex form of the quadratic function with vertex    (h, k)

the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8

the <u>maximum height of 2</u> means  k = 2

So:

f(x) = a(x - (-8))² + 2

f(x) = a(x + 8)² + 2   - the vertex form of the quadratic function with vertex   (-8, 2)

The parabola passing through the point (-7, -1) means that if x = -7 then        f(x) = -1

so:

    -1 = a(-7 + 8)² + 2

 -1 -2 = a(1)² + 2 -2

      -3 = a

Threfore:

The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:

                                 <u>f(x) = -3(x + 8)² + 2</u>

8 0
3 years ago
After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parab
Gekata [30.6K]

We can answer the first part of the question not taking intersecting function into account. The domain of y=-x^{2}+36 is all the numbers, x∈(-∞, +∞) and the range is y∈(-∞, 36]. We can observe these results with the help of a graph, as well. Since we are talking about the rainbow, the values above the ground level will make sense. In this case, we will take into account the range as it changes between 0 and 36, included and the domain between -6 and 6. Here (0;36) is the y-intercept and (-6;0) and (6;0) are the x-intercepts of the parabola.


Since in our problem, the linear function that intersects parabola is not given, we have to provide it by ourselves according to the conditions of the problem. It could be any line intersecting parabola in two points. One important point is that the y-intercept has to be no more than 36. Considering these conditions, we can set our linear function to be y=0.5x+5. We can observe the points that we included in the table (they have been given with orange dots in the graph and the table is attached below). We can see that the values of the function (values of y) are positive. Indeed, we are discussing the part of the rainbow above the ground level.


The system of equations with linear and quadratic functions has got two solutions and we can observe that result from the graph. The solutions are (-5.823; 2.088) and (5.323; 7.662). The solutions are the intersection points.

7 0
3 years ago
Find the indicated values where g(t)=t^2-t and f(x)=1+x g(f(0))+f(g(0))
Blababa [14]

Answer:

1

Step-by-step explanation:

First find f(0) and g(0). These are the values where x=0 in each function.

f(0) = 1+0 = 1

g(0) = 1^2 - 1 = 1-1 = 0

So f(0) = 1 and g(0) = 0.

Now substitute f(0) = 1 into g(t).

g(1) = 1^2 -1 = 1-1 = 0.

So g(f(0)) = 0.

Now substitute g(0) = 0 into f(t).

f(0) = 1 + 0 = 1.

So f(g(0)) = 1.

Add the values 0 and 1 to get 0+1 = 1.

6 0
3 years ago
Read 2 more answers
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