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Schach [20]
3 years ago
15

Find the real solutions of the following equation. If K= x + 1/x-1 and k^2- k=20, find x.

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0
X
=
k
2
+
1
2
First one……..
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What are the common factors of 35 and 60?
Ksivusya [100]
I think it is 5 !!!!!!!!!!!!!!

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3 years ago
Find the value of<br> 10!<br> (10-3)<br> A. 70<br> B. 120<br> O C. 5040<br> O D. 720
GarryVolchara [31]

Answer:

The answer is option D.

Step-by-step explanation:

\frac{10!}{(10 - 3) ! }  =  \frac{10!}{7!}  =  \frac{3628800}{5040}  = 720

Hope this helps you

8 0
3 years ago
What is 1/6 times 1/6
Murljashka [212]
1/6* 1/6. Multiply the top number and the bottom numbers and you have 1/36.
5 0
3 years ago
Read 2 more answers
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
Two angles are complementary. mZT is (3x + 17)° and mZW is 19°<br> Solve for x and for mZT.
natima [27]

Answer:

x = 18

mZT = 71º

Step-by-step explanation:

Complementary angles total 90º

(3x + 17) + 19 = 90

Subtract 19 from both sides

3x + 17 = 71

mZT = 71º

Subtract 17 from both sides

3x = 54

Divide both sides by 3

x = 18

5 0
3 years ago
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