3 years ago

Find the real solutions of the following equation. If K= x + 1/x-1 and k^2- k=20, find x.

Mathematics

1 answer:

ser-zykov [4K]3 years ago

4 0

X
=
k
2
+
1
2
First one……..

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sergejj [24]

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Step-by-step explanation:

$f(x) = \frac{2x + 6}{3x} \\ \\ g(x) = \frac{ \sqrt{x} - 8}{3x}$

To find ( f - g)(x) , subtract g(x) from f(x)

That's

$( f - g)(x) = \frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x}$

Since they have a common denominator that's 3x we can subtract them directly

That's

$\frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x} = \frac{2x + 6 - ( \sqrt{x} - 8) }{3x} \\ = \frac{2x + 6 - \sqrt{x} + 8 }{3x} \\ = \frac{2x - \sqrt{x} + 6 + 8 }{3x}$

We have the final answer as

Hope this helps you

6 0

3 years ago