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3 years ago

Find the real solutions of the following equation. If K= x + 1/x-1 and k^2- k=20, find x.

Mathematics

1 answer:

ser-zykov [4K]3 years ago

4 0

X
=
k
2
+
1
2
First one……..

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Can you please help me with this question and write it out please thank you

Darina [25.2K]

Answer:

dsvfvsdcvdv

Step-by-step explanation:

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6 0

3 years ago

Determine whether each table represents a linear quadratic or exponential function

Kryger [21]

Answer:

Table A: exponencial function

Table B: quadratic function

Table C: linear function

Step-by-step explanation:

Table A:

for x from 1 to 2, Y increased by 6

for x from 2 to 3, Y increased by 18

for x from 3 to 4, Y increased by 54

So we can see that the values of Y are being multiplied by 3 for each increment of x, so this table represents an exponencial function.

Table B:

for x from 1 to 2, Y increased by 6

for x from 2 to 3, Y increased by 10

for x from 3 to 4, Y increased by 14

The increment of Y is higher than a linear increment and smaller than an exponencial increment, so this is the quadratic function.

Table C:

for x from 3 to 6, Y increased by -2

for x from 6 to 9, Y increased by -2

for x from 9 to 12, Y increased by -2

The increment of Y is constant for the same increment of X, so this is a linear function.

7 0

3 years ago

625÷5×6=x what is x

pychu [463]

Answer:

750

Step-by-step explanation:

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7 0

3 years ago

Please help <br> thank you

Scrat [10]

Question 1:

Use the Pythagorean theorem.

If $c^2\ \textless \ a^2+b^2$ , then the angle is acute.
If $c^2=a^2+b^2$ , then the angle is right.
If $c^2\ \textgreater \ a^2+b^2$ , then the angle is obtuse.

$a=18$
$b=80$
$c=81$

$c^2=6561$
$a^2+b^2=324+6400=6724$

$\boxed {c^2\ \textless \ a^2+b^2}$

Thus, the angle is acute.

Question 2:

Take the square root of the area to get the side length.

$\sqrt{200} = \sqrt{100*2} =10 \sqrt{2}$

That's the side length. Since we have a 45-45-90 right triangle if we divide the square across its diagonal, we just multiply the side length by the square root of 2 in order to get the diagonal length.

$10 \sqrt{2} * \sqrt{2}$
$=20$

Your answer is 20 m. Hope this helps! :)

7 0

4 years ago

If y varies directly as x and y = 4 and x = 10, what does x equal when y = 7?

soldi70 [24.7K]

Answer: x = 17 $\frac{1}{2}$

Step-by-step explanation:

From the question: y α x

⇒ y = kx

y=4 and x = 10 implies

4 = 10k

k = 4/10

k = 2/5

substitute k = 2/5 into the equation

y = 2/5 x

When y = 7 , the equation becomes

7 = $\frac{2x}{5}$

35 = 2x

35/2 =x

Therefore : 17 $\frac{1}{2}$

x =

8 0

4 years ago