14 is .608, roundedto the nearest percent 14 is 61% of 23
Answer:
No solutions
Step-by-step explanation:
Isolate the absolute value:
|x−1| + 5 = 2
Subtract 5 from both sides:
|x-1| = -3
Since an absolute value can never be equal to a negative number, there are no solutions.
Answer:
A) The best way to picture this problem is with a probability tree, with two steps.
The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.
The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.
If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.
If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.
B) So a person can have a red marble and a blue marble in two ways:
1) Picking the red first and the blue last
2) Picking the blue first and the red last
C) P(R&B) = 3/5 = 60%
Step-by-step explanation:
C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5
Given :
A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path.
To Find :
Which number line correctly models this situation and the total number of distance markers.
Solution :
It is given that their are markers every 1/4 part of mile.
So, their are 4 markers per mile.
Numbers of markers in 3 miles long path is :
Therefore, the total number of distance markers in 3 mile path is 12.
Hence, this is the required solution.
Step-by-step explanation:
V = (12*4*5) + (2*3*5) + (5*3*5) + (12*4*5)
V = 240 + 30 + 75 + 240
V = 585 cm^3
