Newton's Law of Cooling states that the change
of the temperature of an object is proportional to the difference between its
own temperature and the ambient temperature over time.
Therefore when expressed mathematically, this is equivalent
to:
dT = - k (T – Ts) dt
dT / (T – Ts) = - k dt
Integrating:
ln [(T2– Ts) / (T1– Ts)] = - k (t2 – t1)
Before we plug in the values, let us first convert the
temperatures into absolute values R (rankine) by adding 460.
R = ˚F + 460
T1 = 200 + 460 = 660 R
Ts = 70 + 460 = 530 R
ln [(T2– 530) / (660 – 530)] = - 0.6 (2 - 0)
T2 = 569.16 R
T2 = 109 ºF
Answer: After 2 hours, it will be 109 ºF
Answer:
15.7
Step-by-step explanation:
'6' is in the tenths place in 15.6895. The digit following this '6' is '8,' which requires rounding up this '6' to '7.'
Thus, to the nearest tenth, we get 15.7.
Answer:
Step-by-step explanation:
Pay attention to order of vertices when comparing the congruent parts or figures.
C and D as well as B and E are corresponding vertices according to angle marks and side marks.
-3*-2*-2=6*-2=-12 because negative multiplied by negative is positive
Answer:
q = 3 + 1/2r
Step-by-step explanation:
10q - 5r = 30
We want to solve for q
Add 5r to each side
10q - 5r+5r = 30+5r
10q = 30+5r
Divide by 10
10q/10 = 30/10 +5r/10
q = 3 + 1/2r
