Answer: c)
.
Step-by-step explanation:
Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

Given function :
Interval : [0,3]
Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that


Since 
then, at x=c, 
From (i) and (ii), we have

Hence, the correct option is c)
.
Answer:
The answer is D. 12 pounds
Step-by-step explanation:
Math is not my strong suit, so I apologize if this is wrong.
Answer:
$569.50
Step-by-step explanation:
15% deduction from the initial price(100%) will have us remaining with 85%
100% = 670
85% = <u>85% x 670</u>
100%
= $569.50
Answer:
4x +2y=10
2y=-4x+10
y=-2x+5
<u>y-3=-2</u>
x-7
y-3=-2x+14
y=-2x+17
Step-by-step explanation:
I'm not sure what the question is. If this is true or false, then the answer is true. The top part of a fraction (the numerator) represents part of the whole. The bottom number (the denominator) represents the whole number.
Example:
3/4
Three is part of the whole, which is four
Hope this helps! :)