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4 years ago

G(x)=4x^2-3x+7 find g(3)

2 answers:

8 0

G(x) = 4x^2 - 3x + 7
find g(3)

Answer:

Plug it in:

g(3) = 4(3)^2 - 3(3) + 7

g = 4(9) - 9 + 7

simplify:

g = 36 - 9 + 7

g = 34 <<<< the answer to this.

Hope this helped!

~Shane

Olenka [21]4 years ago

7 0

As g(x) is 4x²-3x+7 and we need to find g(3) it means in the given polynomial we have to replace the variable X with 3
So here You go,
4(3²) -3(3)+7 i.e. __________34
HOPE THIS HELPS

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3 years ago

QUESTION 2. the feasible region shows the number of chairs x and tables y that a furniture company can build each week.

GalinKa [24]

Answer:

Part a) The company can not build 12 chairs and 5 tables

Part b) The company can build 18 chairs and 3 tables

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Step-by-step explanation:

we know that

If a ordered pair is a solution, then the ordered pair must be belong to the feasible region of the graph

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In this problem we have the ordered pair A(12,5)

Plot and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point A is not on the feasible region

therefore

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Part b) Can the company build 18 chairs and 3 tables?

In this problem we have the ordered pair B(18,3)

Plot and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point B is on the feasible region

therefore

The company can build 18 chairs and 3 tables

Part c) One week, the company decides to build 4 tables. how many chairs can the company build?

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Find the value of x in the graph

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3 years ago

Please help me find limit

cluponka [151]

9514 1404 393

Answer:

-13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

$\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}$