Question

If h (x) = {(-2,3), (0,4), (1,6), (2, 9)} then what set of values represent h-1 (x) ?

Answer 1

Answer:

$h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}$

Step-by-step explanation:

Given: $h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}$

To find: $h^{-1}(x)$

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

$h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}$

$h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}$