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vova2212 [387]
3 years ago
5

ms.lieber takes 4 hours to drive 210 miles from her home to yosemite National Park . if Miss Lieber's average speed for the firs

t two hours is 60 miles per hour, find her average speed for the last 2 hours
Mathematics
2 answers:
Fed [463]3 years ago
8 0
This is correlation between distance-time-speed that we will use in answering
d = vt
t = d/v
v = d/t
d stands for distance, v stands for velocity/speed, t stands for time

First, we should count the distance she took for the first two hours
d = vt
d = (60)(2)
d = 120
For the first two hours, she took 120 miles

Second, calculate the distance for the next two hours
d = total distance - first distance
d = 210 - 120
d = 90
The remaining distance is 90 miles

Third, calculate the speed for the next 2 hours
s = d/t
s = 90/2
s = 45
The speed for the last two hours is 45 miles per hour

Answer: 45 miles/hour
adoni [48]3 years ago
7 0
60 x 2 = 120 miles for the 2 hours,
210 - 120 = 90
AVG speed for the last 2 hours is 45 MPH
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What is the solution of the system of equations? Show your work.
scZoUnD [109]

Answer:

1.Solve for y in 2x+y=-3

y=-3-2x

2. Substitute y= -3 - 2x into 4x-2y=10

8x+6=10

3 Solve for x in 8x+6=10

x=1/2

​

4. Substitute x=1/2 into y = - 3 - 2x

y= -4

5. So you get...,

x=1/2

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​

Step-by-step explanation:

you're welcome :)

3 0
2 years ago
An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that
qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100

#First find F_x and probability distribution function ,f_x(x):

F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}

#Have determined the probability distribution unction ,f_x(x), we calculate the Expectation of the random variable X:

E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200}  dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\

#We then calculate E(X^2):

E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28

Hence, the Var(X) is 764.28  

4 0
3 years ago
On Friday night, Alex ate a large pizza for dinner and had LaTeX: \frac{3}{5}3 5 of the pizza left over when he was done. On Sat
ludmilkaskok [199]

Answer:

Alex ate \frac{3}{10} of the large pizza on Saturday.

Step-by-step explanation:

Given:

Amount of Pizza which was left over on Friday = \frac{3}{5}

Amount of Pizza ate on Saturday  = \frac{1}{2} of the Amount of Pizza was left over on Friday

We need to find how much did Alex eat on Saturday.

Solution;

Since we know that Alex ate on Saturday \frac{1}{2} of the Amount of Pizza which was left over on Friday.

So to find the amount he ate n Saturday we will Multiply \frac{1}{2} with the Amount of Pizza which was left over on Friday.

framing in equation form we get;

Alex ate on Saturday = \frac{1}{2}\times \frac{3}{5}= \frac{3}{10}

Hence Alex ate \frac{3}{10} of the large pizza on Saturday.

4 0
3 years ago
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