I need very urgent help with this

Mathematics

1 answer:

Leto [7]3 years ago

7 0

Answer:

-5, -2, -1, 2

Step-by-step explanation:

You can find the answer by trying the given possible answers out.

You might be interested in

(Squreroot x+2)(squreoot x-2)=0

yuradex [85]

Answer:

$\boxed{ \ x = 2 \ or \ x = -2 \ }$

Step-by-step explanation:

I understand that you want to solve this equation

$\sqrt{x+2}\sqrt{x-2}=0$

<=>

$\sqrt{(x+2)(x-2)}=0$

<=>

$(x+2)(x-2)=0$

<=>

x = 2 or x = -2

hope this helps

if your question is $(\sqrt{x}+2)(\sqrt{x}-2) = 0$

then this is $(\sqrt{x})^2-4 = 0\\ x = 4$

7 0

3 years ago

The zeros of the function f(x) = (x + 2)^2 - 25 are

blondinia [14]

$The\ zeros\ of\ a\ function\ f(x)\ is\ when\ f(x)=0.\\------------------------\\f(x)=(x+2)^2-25\\the\ zeros,\ if\ f(x)=0\iff(x+2)^2-25=0\\\\(x+2)^2-5^2=0\ \ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\(x+2-5)(x+2+5)=0\\\\(x-3)(x+7)=0\iff x-3=0\ or\ x+7=0\\\\x-3=0\ \ \ |add\ 3\ to\ both\ sides\\\boxed{x=3}\\or\\x+7=0\ \ \ \ \ |subtract\ 7\ from\ both\ sides\\\boxed{x=-7}\\\\Answer:\boxed{(4)\ -7\ and\ 3}$