<img src="https://tex.z-dn.net/?f=4x%5E%7B2%7D%20%2B28x%2B49%3D0" id="TexFormula1" title="4x^{2} +28x+49=0" alt="4x^{2} +28x+49=

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3 years ago

10

0" align="absmiddle" class="latex-formula">

1 answer:

Harman [31]3 years ago

6 0

Answer:

x = -7/2 multiplicity 2.

Step-by-step explanation:

4x^2 + 28x + 49 = 0

(2x + 7)(2x + 7) = 0

This is a perfect square.

2x + 7 = 0, so:

x = -7/2 multiplicity 2.

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