.0091 rounded to the nearest thousandths would be .009
Answer:
43740
Step-by-step explanation:
its an exponential factor of 3 just multiply each answer by 3 to get the next one up
We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
Full question plzz we need to know what the core is
Answer:
The sample size is 
Step-by-step explanation:
From the we are told that
The population proportion is p = 0.90
The margin of error is E = 0.01
From the question we are told the confidence level is 95% , hence the level of significance is
=> 
Generally the sample size is mathematically represented as
![n =[ \frac{ Z_{\frac{\alpha }{2} } }{E} ]^2 * p(1-p)](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%20%5Cfrac%7B%20Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%20%7D%7BE%7D%20%5D%5E2%20%2A%20p%281-p%29)
=> ![n =[ \frac{ 1.96 }{0.01} ]^2 * 0.90(1-0.90)](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%20%5Cfrac%7B%201.96%20%20%7D%7B0.01%7D%20%5D%5E2%20%2A%200.90%281-0.90%29)
=>
