Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
Answer:
y = -0.25x - 6
Step-by-step explanation:
You can either just read off the slope m = -0.25 and the intersection with the vertical n = -6 or you form a system of equations from points you choose on the graph. For example:
(0,-6);(4,-7)
The general equation for a line:
y = m*x + n
The two points on the graph form a system of two equations:
1. -6 = m*0 + n
2. -7 = m*4 + n
You can read off n right away fro equation 1:
n = -6
Plugging n into equation 2:
-7 = m*4 - 6 => -1 = m*4 => m = -1/4
Answer:
The answer is 21 units²
Step-by-step explanation:
To find the area of a right triangle you use the formula A=ab/2
So
A=6×7/2 = 21
What is the question? no question has been asked. need more info to solve.
The answer is B, f(x)=1/(x-6)
