2/X^2=4/X+1 times by both denominators
2(x+1)=4(x^2)
2x+2=4x^2
4x^2-2x-2=0
(2x+1)(2x-2)=0
x=2x+1 or 2x-2
x=-1/2 or 1
Step-by-step explanation:
Using pythagorean theorem:
![\begin{gathered} c^2=a^2+b^2 \\ b=\sqrt[]{c^2-a^2} \\ b=\sqrt[]{19^2-17^2} \\ b=\sqrt[]{72} \\ b\approx8.5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7Bc%5E2-a%5E2%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B19%5E2-17%5E2%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B72%7D%20%5C%5C%20b%5Capprox8.5%20%5Cend%7Bgathered%7D)
Answer:
The probability is 0.683
Step-by-step explanation:
To calculate this, we shall be needing to calculate the z-scores of both temperatures
mathematically;
z-score = (x-mean)/SD
From the question mean = 78 and SD = 5
For 73
z-score = (73-78)/5 = -5/5 = -1
For 83
z-score = (83-78)/5 = 5/5 = 1
So the probability we want to calculate is within the following range of z-scores;
P(-1 <z <1 )
Mathematically, this is same as ;
P(z<1) - P(z<-1)
Using the normal distribution table;
P(-1<z<1) = 0.68269 which is approximately 0.683
