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labwork [276]
3 years ago
11

Solve the system by substitution: y = -3x + 10 y=-3x + 4 Please show the steps!

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

x=1, y=7

Step-by-step explanation:

y = -3x + 10 - first equation

y=-3x + 4 - second equation

rearrange the expression to

-3x-y= -10

3x-y= -4

pick an equation and simplify; lets pick the second equation

3x-y= -4

\frac{3x}{3} = \frac{-4+y}{3}  

divide 3 by both sides

x= \frac{-4+y}{3} - third equation

substitute the value of x into an equation; lets pick the first equation

-3x-y= -10

-3(\frac{-4+y}{3})- y = -10

simplify. -3 cancels 3 so we are left with

-1(-4+y)-y = -10

simplify

4-y-y= -10

4-2y= -10

subtract 4 from both sides

-2y= -10-4

-2y= -14

divide -2 by both sides

y=7

substitute the value of y, (y=7) in an equation, we are using the second equation

3x-y= -4

3x-7= -4

3x = -4+7

3x= 3

divide 3 by both sides

x=1

so the answer is x=1, y=7

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If f(x)=ln x and g(x)=e^x+1 find f(g(2))-g(f(e)) please help!!
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<h3>ln (e^2 + 1) - (e+ 1)</h3>

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