Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.
<h3>What are BPDU used for?</h3>
A bridge protocol data unit (BPDU) is known to be a kind of a data message that is known to be often transmitted in a local area network to be able to know or find loops in that given network topologies.
Hence, in the case above, In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.
See full question below
. In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block BPDUs?
a. BPDU filter
b. BPDU guard
c. root guard
d. BPDU drop
Learn more about ports from
brainly.com/question/10097616
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Answer: 8
And if you hold shift while typing it, it gives *
