String answer = new String( "" );
do
{
System.out.println( "Question? " );
}
while( answer.length > 0 )
DROP CAP:-
<u>Drop caps are a specific kind of initial letter, large letters that appear at the beginning of a block of text. ... A drop cap is often used to signify that the reader's moved into a significant new section, or that a new chapter's begun.</u>
<u>Drop caps are a specific kind of initial letter, large letters that appear at the beginning of a block of text. ... A drop cap is often used to signify that the reader's moved into a significant new section, or that a new chapter's begun.A drop cap (dropped capital) is a large capital letter used as a decorative element at the beginning of a paragraph or section. The size of a drop cap is usually two or more lines. The following illustration shows your options for positioning a drop cap.</u>
Correct Answer:
False
Reasoning:
The insertion point is the blinking vertical line in your document. It indicates where the letters are going to be put when you type them. When you type the insertion point stays ahead of the words. therefor word inserts text to the right of the insertion point.
Source:
I have taken a Microsoft Word class.
Your question is poorly formatted
<em>#include <stdio.h>
</em>
<em>int main(void) {
</em>
<em>int i, t[4];
</em>
<em>t[3] = 0;
</em>
<em>for (i = 1; i >= 0; i--)
</em>
<em>t[i] = t[3] * i;
</em>
<em>printf("%d", +t[1]);
</em>
<em>return 0;
</em>
<em>}</em>
Answer:
It outputs 0
Explanation:
I'll start my explanation from the third line
This line declares an integer variable i and an array of 4 elements of type integer
<em>int i, t[4];
</em>
<em />
This line initialize the 3rd index element to 0
<em>t[3] = 0;
</em>
<em />
The next two lines is an iteration;
The first line of the iteration iterates the value of i in descending order from 1 to 0
<em>for (i = 1; i >= 0; i--)
</em>
<em />
This line of the iteration calculates t[1] as t[3] * i and t[0] as t[3] * i; Since t[3] is 0; both t[1] and t[0] will be 0
<em>t[i] = t[3] * i;
</em>
<em />
This line prints t[1] which is 0
<em>printf("%d", +t[1]);
</em>
