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Pavlova-9 [17]
3 years ago
8

Josh will take 10 test in 5 weeks. How many tests will he have taken after 7 weeks?

Mathematics
2 answers:
Basile [38]3 years ago
6 0
I think you have to divide 10 by 5 which gives you 2 then multiply 2 by 7 which gives you 14. So I think he takes 14 tests in 7 weeks
Sedaia [141]3 years ago
3 0
Josh will take 25 test in 7 weeks.
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Solve 3(x+1) -2x= -6
s2008m [1.1K]
3(x + 1) - 2x = -6    |use distributive property: a(b + c) = ab + ac

3x + 3 - 2x = -6

x + 3 = -6    |subtract 3 from both sides

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3 years ago
Factor 20r+60t to identify the equivalent expression
Nadusha1986 [10]

Answer:

\boxed{20(r + 3t)}

Step-by-step explanation:

20r + 60t

Factor out 20 from the expression.

20(r) + 20(3t)

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20(r + 3t)

7 0
3 years ago
.hoi I need a lil help
mihalych1998 [28]

Answer:

10

Step-by-step explanation:

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6 0
3 years ago
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Area: 28.67 sq m and the side is 4.7 m The missing side length is equal to:??? m
Mice21 [21]

Answer:

6.1

Step-by-step explanation:

area =leanth x breath.

if one side=4.7,

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4 0
3 years ago
Which congruence theorems can be used to prove △EFG ≅ △JHG? Check all that apply.
sasho [114]

Answer:

ASA  and AAS

Step-by-step explanation:

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ.  This makes EJ a transversal.  This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent.  We also know that ∠EGF and ∠HGJ are vertical angles and are congruent.  This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent.  Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

4 0
3 years ago
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