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3 years ago

One of the legs of a right triangle measures 8 cm and its hypotenuse measures 14 cm.

Mathematics

1 answer:

Ugo [173]3 years ago

3 0

Answer:

about 11.5 cm.

Step-by-step explanation:

I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.

a^2+b^2=c^2.

"a" and "b" are the values of the legs of the triangle, while "c" is the measure of the hypotenuse. We know that 8cm is the measure of one of the legs, and 14 cm is a measure of the hypotenuse.

8^2+b^2=14^2 simplified: 64+b^2=196

Then, I subtracted 64 on both sides, so I would have "b" by itself.

b^2=132

Next, I found the square root of both b^2 and 132, so I would find the true value of "b."

b=11.4891252931

So, the measure of the other leg rounded to the nearest tenth is about 11.5.

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What is the solution to the system of equations?

Dovator [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}$

$\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}$

$x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10$

4 0

3 years ago

If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193 how much was your original deposit? 29 Origin

Wittaler [7]

Answer:

The original amount deposit is $1641627.68.

Step-by-step explanation:

Given : If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193.

To find : How much was your original deposit?

Solution :

Applying interest formula,

$A=P(1+r)^t$

Where, A is the amount i.e. A=$3783193

P is the principal value i.e. the original deposit

r is the interest rate r=11%=0.11

t is the time t=8 years.

Substitute the value in the formula,

$3783193=P(1+0.11)^8$

$3783193=P(1.11)^8$

$3783193=P\times 2.30$

$P=\frac{3783193}{2.30}$

$P=1641627.68$

Therefore, The original amount deposit is $1641627.68.

3 0

3 years ago

Rewrite 3x+4y=12 in slope-intercept form. Then graph the equation.

frez [133]

Answer:

3x+4y=12

Step-by-step explanation:

7 0

2 years ago

Please answer number 10 I’ll give brainliest thank you!

monitta

I think it's 7 hope its right sorry if not

5 0

3 years ago

It takes 15 electricians 24 days to wire a new housing subdivision. How many days would 18 electricians take to do the same job,

malfutka [58]

So to set up this equation, you have to do
Time1*Workers1=Time2*Workers2
In this case, Time1=24 days, Workers1=15 electricians, and Workers2=18 electricians, and we have to solve for Time2

Thus we get 15*24=18*Time2
Time2=15*24/18=20 days

8 0

3 years ago

Read 2 more answers