First off, the function above is incomplete, however, by the looks of it, likely a quadratic, anyway, the values "x" can safely take on would be all real numbers, thus -∞ < x < +∞
Answer:
(4+√142)/(3) or x=(4-√142) /3
Step-by-step explanation:
(4+√142)/(3) or x=4-√142 /3
Answer: B
Step-by-step explanation:
the parabola having (1,5) as vertex have as equation:
y=k*(x-1)²+5
It is passing through (2,8)
8=k*(2-1)²+5 ==> k+5=8 ==> k=3
equation is y=3(x-1)²+5
Answer B
{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}
SEQUENCE: 6, 18, 54, 162
18/6 = 3
54/18 = 3
162/54 = 3
then, r (common ratio) = 3
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RECURSIVE RULE: r = 3
an = a(n - 1) × r [formula]
ANSWER: an = a(n - 1) × 3
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ITERIATIVE RULE: r = 3, a1 = 6
an = a1 × r^(n - 1) [formula] [ ^(n-1) is an exponent]
ANSWER: an = 6 × 3^(n - 1)
Answer:
f(x) = 3x^2 -21x +36
Step-by-step explanation:
The table gives the x- and y-intercepts, which are sufficient to write the equation in factored form. The x-intercepts of 3 and 4 tell you that factors are (x -3)(x -4). When x=0, this product is (-3)(-4) = 12, but the y-intercept value is 3 times that: 36. So, the factored equation is ...
f(x) = 3(x -3)(x -4)
Multiplying this out, we get ...
f(x) = 3(x^2 -7x +12)
f(x) = 3x^2 -21x +36