All categories

3 years ago

The expanded form 900,000 + 40,000 + 300 + 1 represents the whole number.

Mathematics

2 answers:

WARRIOR [948]3 years ago

8 0

Hey there!

$900,000 = hundred-thousand \\ \\ \\ 40,000 = ten=thousand \\ \\ \\ 300 = hundreds \\ \\ \\ 1 = ones$

In order to find the actual answer to this particular question, you can $add$ the numbers together and that can help you find your result!

$900,000 + 40,000 = 94,000 \\ \\ 94,000 +300 = 94,300 \\ \\ 94,300 + 1 = 94,301$

Answer: $OptionD. 94,301$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

AleksandrR [38]3 years ago

4 0

900,000+40,000+300+1= 940,301.. The answer is D.)

You might be interested in

A study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. Th

andrey2020 [161]

Answer:

The requirements are satisifed since we have the proportion estimated, the sample sizes provided, we assume random sampling for the selection of the data and the distribution for the difference of proportions can be considered as normal

$z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923$

Step-by-step explanation:

Data given and notation

$n_{M}=41$ sample of male selected

$n_{W}=56$ sample of demale selected

$p_{M}=0.57$ represent the proportion of men who dislike anchovies

$p_{WCB}=0.84$ represent the proportion of women who dislike anchovies

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion for men is different from women , the system of hypothesis would be:

Null hypothesis: $p_{M} = p_{W}$

Alternative hypothesis: $p_{M} \neq p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{0.67+0.84}{2}=0.755$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923$

4 0

4 years ago

Pleas help me on this

labwork [276]

Answer:

Step-by-step explanation:

x+x+x

=3x

if i am wrong than sorry