Question

What is the probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner that is divided into 15 equal sectors numbered 1 through 15? Enter your answer, as a simplified fraction, in the boxes.

Answer 1

Answer:

The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is $\frac{3}{10}$

Step-by-step explanation:

To find : What is the probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner that is divided into 15 equal sectors numbered 1 through 15?

Solution :

In flipping a coin outcomes are {H,T} = 2

Favorable outcome of getting head on a coin {H}=1

The probability of flipping heads on a coin is

$P(H)=\frac{1}{2}$

Spinner that is divided into 15 equal sectors numbered 1 through 15.

Favorable outcome of getting a number greater than 6 {7,8,9,10,11,12,13,14,15}=9

The probability of spinning a number greater than 6 is

$P(S)=\frac{9}{15}$

$P(S)=\frac{3}{5}$

Now, The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is given by,

$P(H\text{ and } S)=P(H)\times P(S)$

$P(H\text{ and }S)=\frac{1}{2}\times\frac{3}{5}$

$P(H\text{ and }S)=\frac{3}{10}$

Therefore, The probability of flipping heads on a coin and then spinning a number greater than 6 on a spinner is $\frac{3}{10}$

Answer 2

P(H) = 1/2
P(>6) = 9/15 = 3/5

P(Both H AND >6) = 1/2 * 3/5 = 3/10