Answer:
arc DC = 64
angle DCQ = 32
Step-by-step explanation:
Hello There!
The circumference of a normal circle is 360
Given that arc AD = 98 and having found arc ABC we can find arc DC by subtract the known arcs from 360
360 - 98 - 198 = 64
Hence arc DC = 64
The problem wants us to find angle DCQ having found arc DC
Remember like stated before an included angle is equal to 1/2 its opposite arc
64/2=32
so angle DCQ = 32
Part A
25-9=16
16/2=
8
The length of the rope holding the top right corner of the banner to the post is
8 feet long
Part B
13-9-2=
2 for width
25-8=16 16/2=
8 for length
Use the Pythagorean Theorem

+

=


64+4=

68=


34=c
The length of the rope from the bottom right corner of the banner to the post is
34 feet
I am pretty sure the correct solution would be 43.
You would add all the times: 30+45+30+60+50=215
And then you would divide that number by the amount of values: 215/5
This would give you the answer which is 43. Hope this helps!
Answer:
b)
Step-by-step explanation:
A is invertible if and only if det(A)≠0. Let's compute the determinant of A and find the values k for which it is nonzero.
Using Sarrus's rule, we obtain that

Note that the determinant is a quadratic equation on k, which can be factored as above.
Now the determinant is only zero if k=5 or k=2 (the zeroes of the quadratic polynomial). Therefore, if k≠2,5 the determinant is nonzero so A is invertible.