In the diagram, p is the centroid of abc and pd = 3. find bd.
1 answer:
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I'll do a and e on the first one to show you how to do it
Then See if you can do the rest
a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative
So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18
e. -20 ÷ 5
same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4
You do b, c, d, and f on the first question. Tell me what you get and we'll go from there
</span>Now for the second question <span>
</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)
</span>a.
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator
</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>
but when you times a negative by a negative you get a positive
Now you try b and c; let me know what you get, and we'll go from there!
</span>
Then See if you can do the rest
a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative
So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18
e. -20 ÷ 5
same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4
You do b, c, d, and f on the first question. Tell me what you get and we'll go from there
</span>Now for the second question <span>
</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)
</span>a.
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator
</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>
but when you times a negative by a negative you get a positive
Now you try b and c; let me know what you get, and we'll go from there!
</span>
Let 
, where
and let
be any real constant.
Given this definition of scalar multiplication, we can see right away that there is no identity element
such that
because
and let
Given this definition of scalar multiplication, we can see right away that there is no identity element
because